x^2-60x+160=0

Solution for x^2-60x+160=0 equation:

x^2-60x+160=0

a = 1; b = -60; c = +160;
Δ = b2-4ac
Δ = -602-4·1·160
Δ = 2960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2960}=\sqrt{16*185}=\sqrt{16}*\sqrt{185}=4\sqrt{185}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{185}}{2*1}=\frac{60-4\sqrt{185}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{185}}{2*1}=\frac{60+4\sqrt{185}}{2}
$